6x^2+28x-50=0

Solution for 6x^2+28x-50=0 equation:

6x^2+28x-50=0

a = 6; b = 28; c = -50;
Δ = b2-4ac
Δ = 282-4·6·(-50)
Δ = 1984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1984}=\sqrt{64*31}=\sqrt{64}*\sqrt{31}=8\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-8\sqrt{31}}{2*6}=\frac{-28-8\sqrt{31}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+8\sqrt{31}}{2*6}=\frac{-28+8\sqrt{31}}{12}
$